The diffraction grating (a thin film with hundreds or thousands of tiny parallel lines) produces interference patterns (Young's Experiment) with very sharp, bright fringes compared to a double-slit apparatus.
This is because each fringe produced by a grating is a result of the superposition of light from hundreds of lines.
The first-order fringe is produced when the path difference for light coming from adjacent lines is one wavelength.
The second-order when the path difference is two wavelengths, and so-on.
de=2λ
fg=3λ.
If it shows the 2nd-order, then:
bc=2λ
de=4λ
fg=6λ.
The angle of the n-order fringe can still be found using nλ=dsinθ, or the approximation nλ=dx/L
If light of λ=632nm is incident on a CD, and the distance between the two first-order fringes is 98.4cm on a screen 1.20m from the CD, what is the distance between pits?
Link to Hyperphysics
Link to Diffraction Grating Applet
1 comment:
Homework solution:
Halving the distance between the first-order fringes gives x=0.492m.
The angle of the first order is therefore found from tanθ=0.492/1.20
Therefore θ=22.3°
nλ=dsinθ
n=1
λ=6.32E-7
sinθ=0.379
d=nλ/sinθ
d=1.67E-6m (1.67μm)
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